Evaluated Slots
The evaluated slot mechanism is a tool to fully evaluate a constant integral expression and avoid the lazy evaluation normally performed by the preprocessor.
Tutorial
In order to understand the use of such a mechanism, I will start with a simple file-iteration example.
Consider the following scenario....
for (int i = 0; i < 10; ++i) {
for (int j = 0; j < i; ++j) {
// ... use i and j
}
}
The above is a simple runtime model of the following multidimensional file-iteration....
// file.hpp
#if !BOOST_PP_IS_ITERATING
#ifndef FILE_HPP_
#define FILE_HPP_
#include <boost/preprocessor/iteration/iterate.hpp>
#define BOOST_PP_ITERATION_PARAMS_1 (3, (0, 9, "file.hpp"))
#include BOOST_PP_ITERATE()
#endif // FILE_HPP_
#elif BOOST_PP_ITERATION_DEPTH() == 1
#define I BOOST_PP_ITERATION()
#define BOOST_PP_ITERATION_PARAMS_2 (3, (0, I, "file.hpp"))
#include BOOST_PP_ITERATE()
#undef I
#elif BOOST_PP_ITERATION_DEPTH() == 2
#define J BOOST_PP_ITERATION()
// use I and J
#undef J
#endif
There is a problem with the code above.
The writer expected I to refer the previous iteration frame.
However, that is not the case.
When the user refers to I, he is actually referring to BOOST_PP_ITERATION(),
not the value of BOOST_PP_ITERATION() at the point of definition.
Instead, it refers to exactly the same value to which J refers.
The problem is that the preprocessor always evaluates everything with lazy evaluation.
To solve the problem, we need I to be evaluated here:
// ...
#elif BOOST_PP_ITERATION_DEPTH() == 1
#define I BOOST_PP_ITERATION()
// ...
Fortunately, the library offers a mechanism to do just that: evaluated slots.
The following code uses this mechanism to "fix" the example above...
// ...
#elif BOOST_PP_ITERATION_DEPTH() == 1
#define BOOST_PP_VALUE BOOST_PP_ITERATION()
#include BOOST_PP_ASSIGN_SLOT(1)
#define I BOOST_PP_SLOT(1)
// ...
There are two steps to the assignment of an evaluated slot.
First, the user must define the named external argument BOOST_PP_VALUE.
This value must be an integral constant expression.
Second, the user must include BOOST_PP_ASSIGN_SLOT(x), where x is the particular slot to be assigned to (1 to BOOST_PP_LIMIT_SLOT_COUNT).
This will evaluate BOOST_PP_VALUE and assign the result to the slot at index x.
To retrieve a slot's value, the user must use BOOST_PP_SLOT(x).
In the case above, I is still lazily evaluated.
However, it now evaluates to BOOST_PP_SLOT(1).
This value will not change unless there is a subsequent call to BOOST_PP_ASSIGN_SLOT(1).
Advanced Techniques
The slot mechanism can also be used to perform calculations:
#include <iostream>
#include <boost/preprocessor/slot/slot.hpp>
#include <boost/preprocessor/stringize.hpp>
#define X() 4
#define BOOST_PP_VALUE 1 + 2 + 3 + X()
#include BOOST_PP_ASSIGN_SLOT(1)
#undef X
int main(void) {
std::cout
<< BOOST_PP_STRINGIZE(BOOST_PP_SLOT(1))
<< &std::endl;
return 0;
}
In essence, anything that can be evaluated in an #if (or #elif) preprocessor directive is available except the defined operator.
It is even possible to use a particular slot itself while reassigning it:
#define BOOST_PP_VALUE 20
#include BOOST_PP_ASSIGN_SLOT(1)
#define BOOST_PP_VALUE 2 * BOOST_PP_SLOT(1)
#include BOOST_PP_ASSIGN_SLOT(1)
BOOST_PP_SLOT(1) // 40
See Also
- Paul Mensonides